Using the spin-only formula, the hybridisation and magnetic moment of [Cr(H2O)6]^3+ (octahedral, Cr = 24) are respectively:

JEE Main levelSingle correct optionDifficulty 2 of 3cc177

Using the spin-only formula, the hybridisation and magnetic moment of $[Cr (H X_{2} O) X_{6}] X^{3 +}$ (octahedral, Cr = 24) are respectively:

Cr X^{3 +}

3 d^{3}

, so the three electrons occupy three separate

3 d

orbitals whatever the ligand strength. Two

3 d

orbitals remain empty, so

d^{2} s p^{3}

(inner orbital) is used. With

n = 3

μ = 3 \times 5 = 3.87

BM.