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Basic Inorganic Nomenclature and Oxidation Number
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Oxidation number determination including fractional and unusual cases
JEE Main level
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Difficulty 2 of 3
bn021
Select the species in which the named element has a NON-INTEGER (fractional) average oxidation number (H is
+
1
, O is
−
2
).
A
S in
S
X
4
O
X
6
X
2
−
B
N in
HN
X
3
C
Fe in
Fe
X
3
O
X
4
D
C in
C
X
6
H
X
12
O
X
6
Answer: A, B, C
HN
X
3
:
1
+
3
x
=
0
gives
x
=
−
3
1
.
S
X
4
O
X
6
X
2
−
:
4
x
−
12
=
−
2
gives
+
2.5
.
Fe
X
3
O
X
4
:
3
x
−
8
=
0
gives
+
3
8
.
C
X
6
H
X
12
O
X
6
:
6
x
+
12
−
12
=
0
gives
0
, an integer.
Practice Basic Inorganic Nomenclature and Oxidation Number
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