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Basic Inorganic Nomenclature and Oxidation Number
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Oxidation number determination including fractional and unusual cases
JEE Main level
Single correct option
Difficulty 2 of 3
bn020
In which of the following does nitrogen have the oxidation number
−
2
(H is
+
1
, O is
−
2
, Na is
+
1
)?
A
N
X
2
H
X
4
B
HN
X
3
C
NaNH
X
2
D
NH
X
2
OH
Answer: A
N
X
2
H
X
4
:
2
x
+
4
=
0
gives
−
2
.
NH
X
2
OH
:
x
+
2
−
2
+
1
=
0
gives
−
1
.
NaNH
X
2
:
1
+
x
+
2
=
0
gives
−
3
.
HN
X
3
:
1
+
3
x
=
0
gives
−
3
1
.
Practice Basic Inorganic Nomenclature and Oxidation Number
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