MolSynapsequestion bank
MolSynapse / Question bank / Basic Inorganic Nomenclature and Oxidation Number / Oxidation number determination including fractional and unusual cases
JEE Main levelSingle correct optionDifficulty 2 of 3bn018

Assertion (A): The average oxidation number of sulfur in is , a fraction, although no individual sulfur atom can have a fractional oxidation number. Reason (R): In the tetrathionate structure the two terminal S atoms are and the two inner S atoms (bonded only to S) are . Choose the correct option.

  1. ABoth A and R are true but R is not the correct explanation of A
  2. BA is true but R is false
  3. CBoth A and R are true and R is the correct explanation of A
  4. DA is false but R is true

Answer: C

Each terminal S sits in an group of charge , so gives ; the S-S bonds contribute zero, so each inner S is . Average . Both statements are true and R explains why the average is fractional.
Practice Basic Inorganic Nomenclature and Oxidation Number More on Oxidation number determination including fractional and unusual cases

More questions on Oxidation number determination including fractional and unusual cases