Match the species in Column I with the oxidation number of the named metal in Column II (CN is CN-, CO is a neutral ligand). Column I: (P) Fe in K4[Fe(CN)6]; (Q) Ni in Ni(CO)4; (R) Mn in KMnO4; (S) Fe in K3[Fe(CN)6]. Column II: (1) 0; (2) +2; (3) +3; (4) +7.

JEE Main levelSingle correct optionDifficulty 2 of 3bn019

Match the species in Column I with the oxidation number of the named metal in Column II (CN is $CN X^{-}$ , CO is a neutral ligand). Column I: (P) Fe in $K X_{4} [Fe (CN) X_{6}]$ ; (Q) Ni in $Ni (CO) X_{4}$ ; (R) Mn in $KMnO X_{4}$ ; (S) Fe in $K X_{3} [Fe (CN) X_{6}]$ . Column II: (1) $0$ ; (2) $+ 2$ ; (3) $+ 3$ ; (4) $+ 7$ .

K X_{4} [Fe (CN) X_{6}]

4 + x - 6 = 0

gives

+ 2

Ni (CO) X_{4}

: CO is neutral so Ni is

0

KMnO X_{4}

1 + x - 8 = 0

gives

+ 7

K X_{3} [Fe (CN) X_{6}]

3 + x - 6 = 0

gives

+ 3

. So P-2, Q-1, R-4, S-3.