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If the standard Gibbs energy change of a reaction is negative, the equilibrium constant at that temperature is

A $K < 1$
B $K > 1$
C $K = 1$
D $K = 0$

Answer: B

Δ G^{\circ} = - RT ln K

. A negative

Δ G^{\circ}

requires

ln K > 0

, that is

K > 1

.

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