JEE Advanced levelOne or more correct optionsDifficulty 3 of 3td110
For CaCOX3(s)CaO(s)+COX2(g), take ΔH∘=+178kJmol−1 and ΔS∘=+161JK−1mol−1 (constant), with Kp=PCOX2/(1bar) and R=8.314Jmol−1K−1. Select the correct statement(s).
AAt 1200K the equilibrium pressure of COX2 exceeds 1bar
BAt 1000K the equilibrium pressure of COX2 is about 1.3bar
CKp reaches 1 at about 1106K
DΔG∘(298K)≈+130kJmol−1
Answer: A, C, D
ΔG∘(298)=178000−298(161)=130kJ. Kp=1 when ΔG∘=0: T=178000/161=1106K. At 1000K, ΔG∘=17000J and Kp=e−2.045=0.129bar, ten times smaller than the quoted 1.3. At 1200K, ΔG∘=−15200J and Kp=4.59>1.