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Thermodynamics and Thermochemistry
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Gibbs energy, spontaneity and relation to equilibrium constant
JEE Main level
Numerical answer
Difficulty 2 of 3
td193
A reaction has
Δ
G
∘
=
−
11.0
kJ
mo
l
−
1
at
300
K
. Taking
R
=
8.314
J
mo
l
−
1
K
−
1
, find the equilibrium constant
K
(nearest integer).
Numerical answer type, tolerance 1.
Answer: 82
ln
K
=
−
Δ
G
∘
/
RT
=
11000/
(
8.314
×
300
)
=
4.4102
, so
K
=
e
4.4102
=
82.3
, about 82.
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