In a Liebig combustion, 0.215 g of an organic compound gave 0.102 g of H2O and 0.352 g of CO2. Using H = 1, C = 12, O = 16, the percentage of hydrogen in the compound is

JEE Main levelSingle correct optionDifficulty 2 of 3si180

In a Liebig combustion, 0.215 g of an organic compound gave 0.102 g of $H X_{2} O$ and 0.352 g of $CO X_{2}$ . Using H = 1, C = 12, O = 16, the percentage of hydrogen in the compound is

All hydrogen of the sample ends up in water: mass of H =

\frac{2}{18} \times 0.102 = 0.01133

g. Percentage H =

\frac{0.01133}{0.215} \times 100 = 5.27%