In a Dumas estimation, 0.315 g of an organic compound gave 47.2 mL of N2 measured at STP (molar volume 22400 mL). With N = 14, the percentage of nitrogen is

JEE Main levelSingle correct optionDifficulty 2 of 3si182

In a Dumas estimation, 0.315 g of an organic compound gave 47.2 mL of $N X_{2}$ measured at STP (molar volume 22400 mL). With N = 14, the percentage of nitrogen is

22400 mL of

N X_{2}

at STP weighs 28 g, so mass of N =

\frac{28}{22400} \times 47.2 = 0.05900

g. %N =

\frac{0.05900}{0.315} \times 100 = 18.73%