The compound shown is one stereoisomer of tartaric acid (2,3-dihydroxybutanedioic acid) drawn with wedges. Its configuration is

At each stereocentre the priorities are $\mathrm{OH}>\mathrm{COOH}>\mathrm{CH}(\mathrm{OH})\mathrm{COOH}>\mathrm{H}$; $\mathrm{COOH}$ wins over the other carbon because its carbon is attached to (O,O,O) against (O,C,H). Applying the sequence rule to the drawing with $\mathrm{H}$ away from the viewer gives $(R)$ at C2 and $(R)$ at C3. Since both centres have the same descriptor and the halves are identical, this is the chiral $(2R,3R)$ enantiomer (natural (+)-tartaric acid), not the meso $(2R,3S)$ form.