The compound shown is one stereoisomer of 3-chlorobutan-2-ol drawn with wedges. Its full configuration is

At C2 the priorities are $\mathrm{OH}$, then $\mathrm{CHClCH}{}_3$ (C attached to Cl,C,H) over $\mathrm{CH}{}_3$, then $\mathrm{H}$; the drawn arrangement gives $(S)$. At C3 the priorities are $\mathrm{Cl}$, then $\mathrm{CH}(\mathrm{OH})\mathrm{CH}{}_3$ (C attached to O,C,H) over $\mathrm{CH}{}_3$, then $\mathrm{H}$; the drawn arrangement gives $(S)$. The compound shown is $(2S,3S)$-3-chlorobutan-2-ol. The two ends are different ($\mathrm{OH}$ versus $\mathrm{Cl}$), so none of the four stereoisomers is meso.