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NEET levelSingle correct optionDifficulty 1 of 3st249

The but-2-ene isomer shown has the two methyl groups on opposite sides of the double bond. Its configuration is

A $(E)$
B $(Z)$
C $(R)$
Dit shows no geometrical isomerism

Answer: A

Each alkene carbon carries

CH X_{3}

(higher priority) and

H

(lower). In the drawing the two higher-priority groups, the methyls, are on opposite sides of the

C = C

bond, which is the

(E)

(trans) isomer.

R

and

S

apply to tetrahedral stereocentres, not to double bonds.

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