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JEE Main levelSingle correct optionDifficulty 2 of 3so024

At a certain temperature pure liquids A and B have vapour pressures $900 mmHg$ and $500 mmHg$ . They form an ideal solution. The mole fraction of A in a liquid mixture that boils at this temperature under $760 mmHg$ is

A0.35
B0.65
C0.84
D0.50

Answer: B

Boiling occurs when total vapour pressure

= 760

:

500 + x_{A} (900 - 500) = 760

. So

x_{A} = 260/400 = 0.65

. The value

0.35

is

x_{B}

.

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