JEE Main levelSingle correct optionDifficulty 2 of 3so023
An ideal solution is prepared from 117g of benzene (molar mass 78) and 46g of toluene (molar mass 92). At the temperature of interest the pure vapour pressures are 120torr (benzene) and 40torr (toluene). The total vapour pressure is
A80torr
B60torr
C160torr
D100torr
Answer: D
Moles: benzene =117/78=1.50, toluene =46/92=0.50, so xb=0.75 and xt=0.25. P=0.75×120+0.25×40=100torr. Swapping the mole fractions gives 60, and the mean of the pure values gives 80.