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JEE Advanced levelNumerical answerDifficulty 3 of 3sb213

In a Solvay plant all the obtained by calcining is recycled, the rest of the comes from limestone (85.0% by mass, impurity inert), and all the resulting is used to recover ammonia from . For 5300 kg of produced, the minimum mass of limestone required is (fill in the value) kg (nearest integer; Na 23, C 12, O 16, Ca 40).

Numerical answer type, answer in kg, tolerance 0.5.

Answer: 5882 kg

Per mole of two moles of are needed for and only one is regenerated on calcination, so one mole must come from (). The resulting (1 mol) is exactly what needs. Moles of kmol, so pure kg and limestone kg, nearest integer 5882.
Practice s-Block Elements More on Important compounds: NaOH, Na2CO3, NaHCO3, CaO, CaCO3, plaster of Paris

More questions on Important compounds: NaOH, Na2CO3, NaHCO3, CaO, CaCO3, plaster of Paris