JEE Advanced levelNumerical answerDifficulty 3 of 3sb213
In a Solvay plant all the COX2 obtained by calcining NaHCOX3 is recycled, the rest of the COX2 comes from limestone (85.0% CaCOX3 by mass, impurity inert), and all the resulting CaO is used to recover ammonia from NHX4Cl. For 5300 kg of NaX2COX3 produced, the minimum mass of limestone required is (fill in the value) kg (nearest integer; Na 23, C 12, O 16, Ca 40).
Numerical answer type, answer in kg, tolerance 0.5.
Answer: 5882 kg
Per mole of NaX2COX3 two moles of COX2 are needed for NaHCOX3 and only one is regenerated on calcination, so one mole must come from CaCOX3 (CaCOX3CaO+COX2). The resulting CaO (1 mol) is exactly what 2NHX4Cl+CaO needs. Moles of NaX2COX3=5300/106=50.0 kmol, so pure CaCOX3=5000 kg and limestone =5000/0.850=5882.35 kg, nearest integer 5882.