In the Solvay process with complete recycling of NH3 and CO2, the mass of CaCl2 formed as by-product for every 106 g of Na2CO3 produced is (Ca 40, Cl 35.5)

JEE Advanced levelSingle correct optionDifficulty 3 of 3sb212

In the Solvay process with complete recycling of $NH X_{3}$ and $CO X_{2}$ , the mass of $CaCl X_{2}$ formed as by-product for every 106 g of $Na X_{2} CO X_{3}$ produced is (Ca 40, Cl 35.5)

Per mole of

Na X_{2} CO X_{3}

two moles of

NH X_{4} Cl

are formed, and

2 NH X_{4} Cl + CaO 2 NH X_{3} + CaCl X_{2} + H X_{2} O

gives 1 mol

CaCl X_{2}

. This matches the net equation

2 NaCl + CaCO X_{3} Na X_{2} CO X_{3} + CaCl X_{2}

. 106 g is 1 mol, so the mass is

40 + 71 = 111