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Redox titration calculations
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Difficulty 1 of 3
rx166
Equivalent mass of
KMnO
X
4
when it is reduced to
Mn
X
2
+
in acidic medium is (K = 39, Mn = 55, O = 16):
A
31.6
B
52.7
C
79.0
D
158
Answer: A
Molar mass of
KMnO
X
4
= 158. In acid, Mn changes from +7 to +2, so n-factor = 5. Equivalent mass = 158/5 = 31.6.
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