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Redox titration calculations
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rx167
Equivalent mass of
K
X
2
Cr
X
2
O
X
7
as an oxidant in acidic medium (reduced to
Cr
X
3
+
) is (K = 39, Cr = 52, O = 16):
A
98
B
49
C
294
D
42
Answer: B
Molar mass = 294. Two Cr atoms each change from +6 to +3, so n-factor = 6. Equivalent mass = 294/6 = 49.
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