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NEET levelSingle correct optionDifficulty 1 of 3rx170

The normality of a 0.02 M solution of $KMnO X_{4}$ used in acidic medium (reduction to $Mn X^{2 +}$ ) is:

A $0.10 N$
B $0.02 N$
C $0.06 N$
D $0.04 N$

Answer: A

Normality = molarity x n-factor =

0.02 \times 5 = 0.10

N.

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