JEE Main levelNumerical answerDifficulty 2 of 3rx136
Use Fe = 56, S = 32, O = 16. A 5.00g sample containing FeSOX4 and inert impurity is dissolved in dilute acid and titrated with 0.100MKX2CrX2OX7 (CrX2OX7X2−2CrX3+); 24.0mL is required. Find the mass percentage of FeSOX4 (two decimals).
Numerical answer type, answer in %, tolerance 0.05.
Answer: 43.78 %
KX2CrX2OX7: 24.0×0.100=2.40 mmol, n=6, so FeX2+=14.4 mmol. Mass =14.4×10−3×152=2.1888g. Percentage =2.1888/5.00×100=43.78%.