JEE Main levelNumerical answerDifficulty 2 of 3rx133
Use Na = 23, C = 12, O = 16. In acidic medium KMnOX4 oxidises oxalate to COX2 (MnOX4X− reduced to MnX2+). Find the volume (in mL, nearest integer) of 0.04MKMnOX4 needed for 1.34g of NaX2CX2OX4.
Numerical answer type, answer in mL, tolerance 0.5.
Answer: 100 mL
M(NaX2CX2OX4)=134, so moles =0.01, equivalents =0.01×2=0.02. N(KMnOX4)=0.04×5=0.2. V=0.02/0.2=0.1L=100mL.