JEE Main levelNumerical answerDifficulty 2 of 3rx138
Use Fe = 56, O = 16. FeX3OX4 (an oxide containing FeX2+ and FeX3+) is dissolved in dilute acid, and only its FeX2+ is oxidised by acidified KMnOX4 (to MnX2+). Find the volume in mL (nearest integer) of 0.02MKMnOX4 needed for 2.32g of FeX3OX4.
Numerical answer type, answer in mL, tolerance 0.5.
Answer: 100 mL
FeX3OX4 = FeO⋅FeX2OX3 has one FeX2+ per formula unit, so n=1. M=232, moles =0.01, equivalents =0.01. N(KMnOX4)=0.1, so V=0.01/0.1=0.1L=100mL.