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Oxidation number rules and unusual cases
JEE Main level
Single correct option
Difficulty 2 of 3
rx020
The oxidation number of sulfur in peroxodisulfuric acid,
H
X
2
S
X
2
O
X
8
, which has one O-O peroxide bond, is
A
+
7
B
+
6
C
+
5
D
+
8
Answer: B
Two O atoms are
−
1
and six are
−
2
:
2
(
+
1
)
+
2
x
+
2
(
−
1
)
+
6
(
−
2
)
=
0
gives
x
=
+
6
. Ignoring the peroxide bond gives
+
7
, which is impossible for sulfur.
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