JEE Advanced levelOne or more correct optionsDifficulty 3 of 3rg053
For a van der Waals gas expanded as Z=1+B/Vm+C/Vm2+…, which statements are correct?
AB=b−a/RT
BC=b2
CB changes sign at T=a/Rb
DC is negative at all temperatures
Answer: A, B, C
From Z=1−b/Vm1−RTVma=1+Vmb+Vm2b2+⋯−RTVma, so B=b−a/RT and C=b2 (A and B true). B=0 when RT=a/b, the Boyle temperature (C true). C=b2 is always positive (D false).