At 273 K the second virial coefficient of a gas is B = -24.0 mL mol^-1. Using Z = 1 + (BP)/(RT) and R = 0.0821 L atm K^-1 mol^-1, the pressure in atm (one decimal) at which Z = 0.980 is

JEE Advanced levelNumerical answerDifficulty 3 of 3rg052

At $273 K$ the second virial coefficient of a gas is $B = - 24.0 mL mo l^{- 1}$ . Using $Z = 1 + \frac{BP}{RT}$ and $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ , the pressure in atm (one decimal) at which $Z = 0.980$ is

Numerical answer type, answer in atm, tolerance 0.2.

Z - 1 = BP / RT

, so

P = \frac{( Z - 1 ) RT}{B} = \frac{( - 0.020 ) ( 0.0821 \times 273 )}{- 0.0240} = \frac{- 0.4483}{- 0.0240} = 18.68 atm

, i.e.

18.7 atm