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JEE Main levelOne or more correct optionsDifficulty 2 of 3rg050

A gas has second virial coefficient $B = - 0.120 L mo l^{- 1}$ at a certain temperature. Neglecting higher virial terms, which statements are correct?

AAt a molar volume of $2.40 L mo l^{- 1}$ the compressibility factor is $0.95$
BThe gas is below its Boyle temperature
CAttractive forces dominate over repulsive forces at this temperature
DThe compressibility factor increases above 1 as the molar volume is increased

Answer: A, B, C

Z = 1 + B / V_{m} = 1 - 0.120/2.40 = 0.95

(A true). A negative

B

means

T

is below

T_{B}

and attractions dominate (B and C true). As

V_{m}

increases,

B / V_{m}

tends to zero from below, so

Z

approaches 1 from below and never exceeds 1 (D false).

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