At 20 atm and 400 K the compressibility factor of CO2 (molar mass 44 g mol^-1) is 0.92. Using R = 0.0821 L atm K^-1 mol^-1, the density of the gas in g L^-1 (two decimals) is

JEE Main levelNumerical answerDifficulty 2 of 3rg008

At $20 atm$ and $400 K$ the compressibility factor of $CO X_{2}$ (molar mass $44 g mo l^{- 1}$ ) is $0.92$ . Using $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ , the density of the gas in $g L^{- 1}$ (two decimals) is

Numerical answer type, answer in g/L, tolerance 0.02.

From

Z = PM / (ρRT)

ρ = \frac{PM}{ZRT} = \frac{20 \times 44}{0.92 \times 0.0821 \times 400} = \frac{880}{30.213} = 29.127 g L^{- 1}

, i.e.

29.13 g L^{- 1}

. The real gas is denser than the ideal value

\frac{880}{32.84} = 26.80 g L^{- 1}