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JEE Main levelSingle correct optionDifficulty 2 of 3rg005

At a certain pressure and temperature a real gas has compressibility factor $Z = 1.35$ . If an ideal gas under identical conditions and amount would occupy $10.0 L$ , the actual volume of the real gas is

A $7.41 L$
B $10.0 L$
C $13.5 L$
D $18.2 L$

Answer: C

Z = \frac{P V _{real}}{n RT} = \frac{V _{real}}{V _{ideal}}

at the same

P

,

T

and

n

. Therefore

V_{real} = Z V_{ideal} = 1.35 \times 10.0 = 13.5 L

.

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