JEE Advanced levelSingle correct optionDifficulty 3 of 3qa107
Sodium carbonate extract is acidified with dilute HNOX3, boiled, and treated with AgNOX3. A pale yellow curdy precipitate P forms. P is only sparingly soluble in concentrated aqueous NHX3 but dissolves completely in excess aqueous NaX2SX2OX3. The anion in the extract and the formula of the complex formed with thiosulphate (thiosulphate acting as a monodentate ligand) are respectively
AClX− and [Ag(SX2OX3)X2]X3−
BBrX− and [Ag(SX2OX3)X2]X−
CBrX− and [Ag(SX2OX3)X2]X3−
DIX− and [Ag(SX2OX3)]X−
Answer: C
A pale yellow precipitate sparingly soluble in concentrated ammonia is AgBr (AgCl dissolves easily, AgI not at all). With thiosulphate, AgBr+2SX2OX3X2−[Ag(SX2OX3)X2]X3−+BrX−. The charge is +1+2(−2)=−3. Hence bromide and [Ag(SX2OX3)X2]X3−.