Which statements about sodium nitroprusside, Na2[Fe(CN)5NO], and its reaction with sulphide are correct? (Treat NO as NO+.) One or more options may be correct.

Iron is in the +2 oxidation state in the reagent.

The sulphide ion adds to the nitrosyl ligand, so the oxidation state of Fe does not change.

The violet species [Fe(CN)5NOS]^4- is diamagnetic with Fe in the +2 state.

Iron is in the +2 oxidation state in the reagent.

The violet complex anion contains iron in the +3 state.

The sulphide ion adds to the nitrosyl ligand, so the oxidation state of Fe does not change.

The violet species [Fe(CN)5NOS]^4- is diamagnetic with Fe in the +2 state.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3qa106

Which statements about sodium nitroprusside, $Na X_{2} [Fe (CN) X_{5} NO]$ , and its reaction with sulphide are correct? (Treat NO as $NO X^{+}$ .) One or more options may be correct.

AIron is in the $+ 2$ oxidation state in the reagent.
BThe violet complex anion contains iron in the $+ 3$ state.
CThe sulphide ion adds to the nitrosyl ligand, so the oxidation state of Fe does not change.
DThe violet species $[Fe (CN) X_{5} NOS] X^{4 -}$ is diamagnetic with Fe in the $+ 2$ state.

[Fe (CN) X_{5} NO] X^{2 -}

x - 5 + 1 = - 2

gives

x = + 2

. In the sulphide adduct

x - 5 + 1 - 2 = - 4

gives

x = + 2

again, and low-spin

d^{6}

iron(II) with strong-field ligands is diamagnetic. The change is ligand addition, not oxidation of iron. Correct: first three.