Pauling's relation is $χ_{B} - χ_{A} = Δ$ , where $Δ = E (A - B) - E (A - A) E (B - B)$ is expressed in eV. The bond energies of a hypothetical pair are $E (A - A) = 190$ , $E (B - B) = 250$ and $E (A - B) = 300$ kJ/mol. Using $1 eV = 96.5$ kJ/mol, calculate $χ_{B} - χ_{A}$ (answer to two decimal places).

Numerical answer type, tolerance 0.02.

Answer: 0.92

The geometric mean is

190 \times 250 = 217.94

kJ/mol, so

Δ = 300 - 217.94 = 82.06

kJ/mol. In eV this is

82.06/96.5 = 0.850

eV. Then

χ_{B} - χ_{A} = 0.850 = 0.92