Using Pauling values (Cl 3.16, I 2.66, P 2.19), the polarity of the bonds predicts the products of hydrolysis of ICl and PCl3 (water attacks the positive end, the negative end becomes the anion). These products are, respectively,

JEE Advanced levelSingle correct optionDifficulty 3 of 3pt200

Using Pauling values (Cl 3.16, I 2.66, P 2.19), the polarity of the bonds predicts the products of hydrolysis of $ICl$ and $PCl X_{3}$ (water attacks the positive end, the negative end becomes the anion). These products are, respectively,

ICl

chlorine (3.16) is the negative end and iodine (2.66) the positive end, so

OH X^{-}

attaches to I and Cl leaves as chloride:

ICl + H X_{2} O HOI + HCl

. In

PCl X_{3}

chlorine is much more electronegative than phosphorus (2.19), so

OH

attaches to P and P stays in

+ 3

, giving

H X_{3} PO X_{3}

and

HCl

. The

H X_{3} PO X_{4}

option would require oxidation of P.