Ionic potential is defined as phi = z/r (charge over radius in pm). Radii (6-coordinate, pm): Be^2+ 45, Li+ 76, Mg^2+ 72, Ca^2+ 100 and Al^3+ 53.5. Which ion has an ionic potential closest to that of Be^2+?

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JEE Advanced levelSingle correct optionDifficulty 3 of 3pt105

Ionic potential is defined as $ϕ = z / r$ (charge over radius in pm). Radii (6-coordinate, pm): $Be X^{2 +}$ 45, $Li X^{+}$ 76, $Mg X^{2 +}$ 72, $Ca X^{2 +}$ 100 and $Al X^{3 +}$ 53.5. Which ion has an ionic potential closest to that of $Be X^{2 +}$ ?

A $Li X^{+}$
B $Al X^{3 +}$
C $Mg X^{2 +}$
D $Ca X^{2 +}$

Answer: B

Values of

1000 z / r

: Be 44.4, Al 56.1, Mg 27.8, Ca 20.0, Li 13.2. Differences from Be: Al 11.6, Mg 16.7, Ca 24.4, Li 31.3. Al is closest, in line with the diagonal relationship of Be and Al.

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Ionic potential is defined as ϕ=z/r (charge over radius in pm). Radii (6-coordinate, pm): BeX2+ 45, LiX+ 76, MgX2+ 72, CaX2+ 100 and AlX3+ 53.5. Which ion has an ionic potential closest to that of BeX2+?

Answer: B

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Ionic potential is defined as $ϕ = z / r$ (charge over radius in pm). Radii (6-coordinate, pm): $Be X^{2 +}$ 45, $Li X^{+}$ 76, $Mg X^{2 +}$ 72, $Ca X^{2 +}$ 100 and $Al X^{3 +}$ 53.5. Which ion has an ionic potential closest to that of $Be X^{2 +}$ ?