The correct decreasing order of ionic radii for V^2+, V^3+, V^4+ and V^5+ is:

JEE Main levelSingle correct optionDifficulty 2 of 3pt084

The correct decreasing order of ionic radii for $V X^{2 +}$ , $V X^{3 +}$ , $V X^{4 +}$ and $V X^{5 +}$ is:

The same nucleus (

Z = 23

) holds progressively fewer electrons as the charge increases, so

Z_{eff}

per electron rises and the radius falls steadily from

V X^{2 +}

V X^{5 +}