Assume complete hydrolysis in which IF7 gives H5IO6 (IF7 + 6H2O -> H5IO6 + 7HF) and XeF6 gives XeO3 (XeF6 + 3H2O -> XeO3 + 6HF). The moles of HF formed from a mixture of 1 mol IF7 and 1 mol XeF6 are

JEE Advanced levelSingle correct optionDifficulty 3 of 3ph204

Assume complete hydrolysis in which $IF X_{7}$ gives $H X_{5} IO X_{6}$ ( $IF X_{7} + 6 H X_{2} O H X_{5} IO X_{6} + 7 HF$ ) and $XeF X_{6}$ gives $XeO X_{3}$ ( $XeF X_{6} + 3 H X_{2} O XeO X_{3} + 6 HF$ ). The moles of HF formed from a mixture of 1 mol $IF X_{7}$ and 1 mol $XeF X_{6}$ are

1 mol

IF X_{7}

gives 7 mol HF, and 1 mol

XeF X_{6}

gives 6 mol HF. Total

= 7 + 6 = 13

mol. Both fluorides give HF in a number equal to the number of F atoms, because every F ends up as

F X^{-}

/HF.