Answer: A, B, C
IX3X− and IClX2X− have 2 bond pairs and 3 lone pairs, so they are sp3d and linear (lone pairs equatorial). IClX4X− has 4 bond pairs and 2 lone pairs, so it is sp3d2 and square planar. BrFX2X+ has 2 bond pairs and 2 lone pairs, so it is bent. Options 1, 2 and 3 are correct.