The total number of lone pairs present on all atoms (central and terminal) in one $\mathrm{ICl}{}_4{}^{-}$ ion plus one $\mathrm{XeF}{}_4$ molecule is

Each of $\mathrm{ICl}{}_4{}^{-}$ and $\mathrm{XeF}{}_4$ is square planar with 2 lone pairs on the central atom. Each terminal Cl or F carries 3 lone pairs, so 4 terminal atoms carry 12. One species has $2+12=14$ lone pairs, so the two together have $14+14=28$.