MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
p-Block Elements: Groups 17 and 18
/
Interhalogen compounds and polyhalide ions
JEE Main level
Single correct option
Difficulty 2 of 3
ph201
Which pair of species has the same number of valence electrons and the same shape?
A
IF
X
7
and
XeF
X
7
X
−
B
ICl
X
4
X
−
and
XeF
X
4
C
BrF
X
3
and
XeF
X
4
D
ClF
X
3
and
XeF
X
2
Answer: B
ICl
X
4
X
−
:
7
+
28
+
1
=
36
valence electrons, square planar;
XeF
X
4
:
8
+
28
=
36
, square planar.
IF
X
7
has 56 and
XeF
X
7
X
−
has 58 electrons.
BrF
X
3
(28, T-shaped) and
XeF
X
4
(36) differ, and
ClF
X
3
(28, T-shaped) and
XeF
X
2
(22, linear) differ.
Practice p-Block Elements: Groups 17 and 18
More on Interhalogen compounds and polyhalide ions
Previous question
Next question
More questions on Interhalogen compounds and polyhalide ions
Which of the following is an interhalogen compound of the type XX'_5?
NEET level
Match the species in List I with the hybridisation and shape in List II. List I: (P) ClF3 (Q) ICl4- (R) XeF2 (S) XeO3. List II: (1) sp^3d, T...
JEE Main level
Match the species in List I with the number of bond pairs and lone pairs on the central atom in List II. List I: (P) ClF3 (Q) XeF4 (R) XeF6 ...
JEE Advanced level
The total number of lone pairs present on all atoms (central and terminal) in one ICl4- ion plus one XeF4 molecule is
JEE Main level
Liquid BrF3 autoionises as 2BrF3 <=> BrF2+ + BrF4-. The shapes (hybridisation of Br) of the cation and the anion are
JEE Advanced level
Assume complete hydrolysis in which IF7 gives H5IO6 (IF7 + 6H2O -> H5IO6 + 7HF) and XeF6 gives XeO3 (XeF6 + 3H2O -> XeO3 + 6HF). The moles o...
JEE Advanced level