Xenon (0.40 mol) is heated with F2 taken in the ratio Xe : F2 = 1 : 20 at 573 K and 60-70 bar, and all the Xe is converted into XeF6. The amount of unreacted F2 left is

JEE Advanced levelSingle correct optionDifficulty 3 of 3ph150

Xenon ( $0.40 mol$ ) is heated with $F X_{2}$ taken in the ratio Xe : $F X_{2}$ = 1 : 20 at 573 K and 60-70 bar, and all the Xe is converted into $XeF X_{6}$ . The amount of unreacted $F X_{2}$ left is

F X_{2}

supplied =

0.40 \times 20 = 8.0 mol

Xe + 3 F X_{2} XeF X_{6}

consumes

0.40 \times 3 = 1.2 mol

. Unreacted

F X_{2}

8.0 - 1.2 = 6.8 mol