Answer: A, B, C
Option 1 is balanced (Xe 2, F 12, Si 1, O 2) and shows XeF6 attacking silica. Option 2 is balanced with H2 reducing Xe(IV) to Xe(0). Option 3 is XeF6 accepting fluoride. Option 4 is wrong because XeF4 donates FX− to give XeFX3X+, not XeFX5X+ (which comes from XeF6).