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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ph159

Which of the following reactions are correctly written?

  1. A
  2. B
  3. C
  4. D

Answer: A, B, C

Option 1 is balanced (Xe 2, F 12, Si 1, O 2) and shows XeF6 attacking silica. Option 2 is balanced with H2 reducing Xe(IV) to Xe(0). Option 3 is XeF6 accepting fluoride. Option 4 is wrong because XeF4 donates to give , not (which comes from XeF6).
Practice p-Block Elements: Groups 17 and 18 More on Noble gases: xenon fluorides, oxides and oxyfluorides

More questions on Noble gases: xenon fluorides, oxides and oxyfluorides