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JEE Advanced levelSingle correct optionDifficulty 3 of 3ph146

$XeF X_{2}$ is treated with $PF X_{5}$ to give salt X, and $XeF X_{6}$ with RbF to give salt Y. The total number of lone pairs on Xe in the xenon-containing ions of X and Y is

A2
B3
C4
D5

Answer: C

X is

[XeF] X^{+} [PF X_{6}] X^{-}

and Y is

Rb X^{+} [XeF X_{7}] X^{-}

. In

XeF X^{+}

:

8 + 7 - 1 = 14

electrons give 1 bond pair and 3 lone pairs on Xe. In

XeF X_{7} X^{-}

:

8 + 7 + 1 = 16

electrons give 7 bond pairs and 1 lone pair. Total =

3 + 1 = 4

.

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