A sample of 7.35 g of XeF6 is hydrolysed completely: XeF6 + 3H2O -> XeO3 + 6HF. If the yield of XeO3 is 80%, the mass of XeO3 obtained is how many grams? Give the answer to two decimals. Atomic masses: Xe = 131, F = 19, O = 16.

JEE Main levelNumerical answerDifficulty 2 of 3ph143

A sample of $7.35 g$ of $XeF X_{6}$ is hydrolysed completely: $XeF X_{6} + 3 H X_{2} O XeO X_{3} + 6 HF$ . If the yield of $XeO X_{3}$ is $80%$ , the mass of $XeO X_{3}$ obtained is how many grams? Give the answer to two decimals. Atomic masses: Xe = 131, F = 19, O = 16.

Numerical answer type, answer in g, tolerance 0.01.

Molar mass of

XeF X_{6}

131 + 114 = 245 g mo l^{- 1}

, so

n = 7.35/245 = 0.0300 mol

. One mole gives one mole of

XeO X_{3}

(

131 + 48 = 179 g mo l^{- 1}

), so theoretical mass =

0.0300 \times 179 = 5.37 g

. At

80%

yield the mass is

5.37 \times 0.80 = 4.30 g