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MolSynapse / Question bank / p-Block Elements: Groups 17 and 18 / Halogen compounds: HX, oxoacids, bleaching powder

JEE Advanced levelNumerical answerDifficulty 3 of 3ph049

Bleaching powder with 36.0 per cent available chlorine (by mass) is treated with excess dilute $H X_{2} SO X_{4}$ . Calculate the mass of bleaching powder needed to liberate 8.96 L of $Cl X_{2}$ measured at STP (molar volume 22.4 L/mol, Cl = 35.5). Give the answer in grams, to the nearest integer.

Numerical answer type, answer in g, tolerance 1.

Answer: 79 g

Available chlorine is the

Cl X_{2}

released by acid, so 1 mol

Cl X_{2}

is 71 g. Moles of

Cl X_{2}

= 8.96/22.4 = 0.40 mol, mass = 0.40 x 71 = 28.4 g. Bleaching powder needed = 28.4/0.360 = 78.89 g, i.e. 79 g.

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