Using E deg(F2/F-) = 2.87 V, E deg(Cl2/Cl-) = 1.36 V, E deg(Br2/Br-) = 1.09 V and E deg(I2/I-) = 0.54 V, select the reaction(s) that are spontaneous under standard conditions.

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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ph050

Using $E^{\circ} (F X_{2} / F X^{-}) = 2.87$ V, $E^{\circ} (Cl X_{2} / Cl X^{-}) = 1.36$ V, $E^{\circ} (Br X_{2} / Br X^{-}) = 1.09$ V and $E^{\circ} (I X_{2} / I X^{-}) = 0.54$ V, select the reaction(s) that are spontaneous under standard conditions.

A $Cl X_{2} + 2 Br X^{-} 2 Cl X^{-} + Br X_{2}$
B $I X_{2} + 2 Br X^{-} 2 I X^{-} + Br X_{2}$
C $F X_{2} + 2 Cl X^{-} 2 F X^{-} + Cl X_{2}$
D $Br X_{2} + 2 Cl X^{-} 2 Br X^{-} + Cl X_{2}$

Answer: A, C

E_{ce ll}^{\circ}

must be positive: A = 1.36 - 1.09 = +0.27 V, B = 1.09 - 1.36 = -0.27 V, C = 0.54 - 1.09 = -0.55 V, D = 2.87 - 1.36 = +1.51 V. So A and D are spontaneous.

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Using E∘(FX2​/FX−)=2.87 V, E∘(ClX2​/ClX−)=1.36 V, E∘(BrX2​/BrX−)=1.09 V and E∘(IX2​/IX−)=0.54 V, select the reaction(s) that are spontaneous under standard conditions.

Answer: A, C

More questions on Trends in halogens

Using $E^{\circ} (F X_{2} / F X^{-}) = 2.87$ V, $E^{\circ} (Cl X_{2} / Cl X^{-}) = 1.36$ V, $E^{\circ} (Br X_{2} / Br X^{-}) = 1.09$ V and $E^{\circ} (I X_{2} / I X^{-}) = 0.54$ V, select the reaction(s) that are spontaneous under standard conditions.