Numerical answer type, tolerance 0.5.
Answer: 4
The secondary cation (CHX3)X2CH−CHX+−CHX2CHX3 gives 2-methylpent-2-ene (H from C2) and (E)- and (Z)-4-methylpent-2-ene (H from C4). The hydride shift gives (CHX3)X2CX+−CHX2CHX2CHX3, which gives 2-methylpent-1-ene and 2-methylpent-2-ene (already counted). Distinct alkenes: 4.