Answer: B
Protonation of one OH and loss of water gives the tertiary cation (CHX3)X2CX+−C(OH)(CHX3)X2. A 1,2-methyl shift gives a cation stabilised by the OH oxygen, (CHX3)X3C−C(CHX3)=OHX+, and loss of HX+ gives pinacolone, (CHX3)X3C−CO−CHX3.