1,1-Dibromopropane is heated with excess NaNH2 (3 equivalents) and the mixture is then treated with water. The product is:

JEE Main levelSingle correct optionDifficulty 2 of 3o4196

1,1-Dibromopropane is heated with excess $NaNH X_{2}$ (3 equivalents) and the mixture is then treated with water. The product is:

A geminal dihalide loses two molecules of HBr with

NaNH X_{2}

to give a terminal alkyne. The third equivalent deprotonates it to sodium propynide,

CH X_{3} C \equiv CNa

, and water then regenerates propyne,

CH X_{3} C \equiv CH