Answer: A
Ionisation gives the secondary cation CHX3−CHX+−C(CHX3)X3. A 1,2-methyl shift from the quaternary carbon gives the tertiary cation (CHX3)X2CX+−CH(CHX3)X2. Ethanol captures this cation to give (CHX3)X2C(OEt)−CH(CHX3)X2, i.e. 2-ethoxy-2,3-dimethylbutane.