A primary amine $CH X_{3} CH X_{2} CH X_{2} NH X_{2}$ can be obtained by Hofmann bromamide degradation of amide P and also by $LiAlH X_{4}$ reduction of nitrile Q. P and Q are respectively

A $CH X_{3} CH X_{2} CONH X_{2}$ and $CH X_{3} CH X_{2} CH X_{2} CN$
B $CH X_{3} CH X_{2} CH X_{2} CONH X_{2}$ and $CH X_{3} CH X_{2} CN$
C $CH X_{3} CH X_{2} CH X_{2} CONH X_{2}$ and $CH X_{3} CN$
D $CH X_{3} CH X_{2} CONH X_{2}$ and $CH X_{3} CH X_{2} CN$

Answer: B

Hofmann degradation loses one carbon, so the amide must have four carbons: butanamide. LiAlH4 reduction keeps the carbon count of the nitrile, so the nitrile must have three carbons: propanenitrile,

CH X_{3} CH X_{2} CN

(giving

CH X_{3} CH X_{2} CH X_{2} NH X_{2}

). Only the first pair fits.

Practice Amines and Aromatic Nitrogen Compounds More on Preparation of amines: Gabriel, Hofmann bromamide, reduction routes

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A primary amine CHX3​CHX2​CHX2​NHX2​ can be obtained by Hofmann bromamide degradation of amide P and also by LiAlHX4​ reduction of nitrile Q. P and Q are respectively

Answer: B

More questions on Preparation of amines: Gabriel, Hofmann bromamide, reduction routes

A primary amine $CH X_{3} CH X_{2} CH X_{2} NH X_{2}$ can be obtained by Hofmann bromamide degradation of amide P and also by $LiAlH X_{4}$ reduction of nitrile Q. P and Q are respectively